Discussion:
I bought this little known secret to winning lotteries for $29.
(too old to reply)
Rick_bari3(at)NOTatBbMaleBUTt@Gmail•ComByteME
2008-05-16 04:07:11 UTC
Permalink
Is it true? Does it work? Have you heard of it before? The formula
says that if you take the combination of any previous lottery draw
comprising a numerical string of all two-digit numbers in ascending
order and multiply them factorially excluding zeros (e.g. 54321
multiplied factorially = 5x4x3x2x1=120) it could yield a secretly
seeded sequence of two digit numbers which if large enough can be
arranged in ascending order with a key to the power ball or mega
number. If the resulting remainder is within 1 digit of an even number
[ :-)) } and divisible serially by 2 until the quotient equals a value
of 27 or less, this will yield the mega number in most state
lotteries. This formula only works with larger sequences of numbers
which is why winning draws rarely if ever correspond to a low sequence
of numbers like the one shown in the factorial example above. This is
no accident. It is designed that way by the statisticians who run the
lottery. This formula allows the lottery prize to be split up among
designated conspirators. My life may be in jeopardy. Good luck and
keep this to yourselves.
-Bozo-
(NUMBeroLOGee=3) cuz
12 is 1+2=3...der4,
De (NUMBers=7) 54321
Wood(LOG) Be,
5+4=9+3=12=1+2=3+2=5
+1=6BUT6=(six=3)&3=
(Three=5)BUT5=(five=
4BUT4=(four=4)BUT4=
(For=3)BUT3=(tree=4)
BUT4=(fore=4)ON-dee-
OtherHAND(fore-can-
BE-calculated/break-
Down.e.g.s(f=5)+(o=
15=1+5=6+(r=18=1+8=9
+6(fromPreviousCalc=
15=6&(e=5)+add(6+5=
11=1+1=2=(two=3)=(th
Ree=5)=(five=4)=(for
=3)=(three=4)=(four=
4)=(four=4)=(four=4)
•••etc•
(BUTTden=?)
U didn,t hear "I.T."
From "ME"•••







.
Rick_bari3(at)NOTatBbMaleBUTt@Gmail•ComByteME
2008-05-16 04:18:56 UTC
Permalink
Is it true? Does it work? Have you heard of it before? The formula
says that if you take the combination of any previous lottery draw
comprising a numerical string of all two-digit numbers in ascending
order and multiply them factorially excluding zeros (e.g. 54321
multiplied factorially = 5x4x3x2x1=120) it could yield a secretly
seeded sequence of two digit numbers which if large enough can be
arranged in ascending order with a key to the power ball or mega
number. If the resulting remainder is within 1 digit of an even number
[ :-)) } and divisible serially by 2 until the quotient equals a value
of 27 or less, this will yield the mega number in most state
lotteries. This formula only works with larger sequences of numbers
which is why winning draws rarely if ever correspond to a low sequence
of numbers like the one shown in the factorial example above. This is
no accident. It is designed that way by the statisticians who run the
lottery. This formula allows the lottery prize to be split up among
designated conspirators. My life may be in jeopardy. Good luck and
keep this to yourselves.
-Bozo-
(NUMBeroLOGee=3) cuz
12 is 1+2=3...der4,
De (NUMBers=7) 54321
Wood(LOG) Be,
5+4=9+3=12=1+2=3+2=5
+1=6BUT6=(six=3)&3=
(Three=5)BUT5=(five=
4BUT4=(four=4)BUT4=
(For=3)BUT3=(tree=4)
BUT4=(fore=4)ON-dee-
OtherHAND(fore-can-
BE-calculated/break-
Down.e.g.s(f=5)+(o=
15=1+5=6+(r=18=1+8=9
+6(fromPreviousCalc=
15=6&(e=5)+add(6+5=
11=1+1=2=(two=3)=(th
Ree=5)=(five=4)=(for
=3)=(three=4)=(four=
4)=(four=4)=(four=4)
���etc�
(BUTTden=?)
U didn,t hear "I.T."
From"ME"•••NOW send
"ME"da $29=(twenty-
Nine=11)=$2=(two=3)=
(Three=5)=(five=4)=
(Four=4)=(four=4)=
(Four=4)=(four=4)=
[REPEAT]••• ��







.
Rick_bari3(at)NOTatBbMaleBUTt@Gmail•ComByteME
2008-05-16 15:11:41 UTC
Permalink
  Edited for stupidity
On May 16, 1:35 am, Bozo <***@37.com> wrote:



- Hide quoted text -
- Show quoted text -
Post by Rick_bari3(at)***@Gmail•ComByteME
Is it true? Does it work? Have you heard of it before? The formula
says that if you take the combination of any previous lottery draw
comprising a numerical string of all two-digit numbers in ascending
order and multiply them factorially excluding zeros (e.g. 54321
multiplied factorially = 5x4x3x2x1=120) it could yield a secretly
seeded sequence of two digit numbers which if large enough can be
arranged in ascending order with a key to the power ball or mega
number. If the resulting remainder is within 1 digit of an even number
[ :-)) } and divisible serially by 2 until the quotient equals a value
of 27 or less, this will yield the mega number in most state
lotteries. This formula only works with larger sequences of numbers
which is why winning draws rarely if ever correspond to a low sequence
of numbers like the one shown in the factorial example above. This is
no accident. It is designed that way by the statisticians who run the
lottery. This formula allows the lottery prize to be split up among
designated conspirators. My life may be in jeopardy. Good luck and
keep this to yourselves.
-Bozo-
(NUMBeroLOGee=3) cuz
12 is 1+2=3...der4,
De (NUMBers=7) 54321
Wood(LOG) Be,
5+4=9+3=12=1+2=3+2=5
+1=6BUT6=(six=3)&3=
(Three=5)BUT5=(five=
4BUT4=(four=4)BUT4=
(For=3)BUT3=(tree=4)
BUT4=(fore=4)ON-dee-
OtherHAND(fore-can-
BE-calculated/break-
Down.e.g.s(f=5)+(o=
15=1+5=6+(r=18=1+8=9
+6(fromPreviousCalc=
15=6&(e=5)+add(6+5=
11=1+1=2=(two=3)=(th
Ree=5)=(five=4)=(for
=3)=(three=4)=(four=
4)=(four=4)=(four=4)
•••etc•
(BUTTden=?)
U didn,t hear "I.T."
From "ME"•••
.- Hide quoted text -
- Show quoted text -
PFF (pretty effing funny)
-Bzpop-- Hide quoted text -
- Show quoted text -
(NUMBeroLOGee=3) cuz
12 is 1+2=3...der4,
De (NUMBers=7) 54321
Wood(LOG) Be,
5+4=9+3=12=1+2=3+2=5
+1=6BUT6=(six=3)&3=
(Three=5)BUT5=(five=
4BUT4=(four=4)BUT4=
(For=3)BUT3=(tree=4)
BUT4=(fore=4)ON-dee-
OtherHAND(fore-can-
BE-calculated/break-
Down.e.g.s(f=5)+(o=
15=1+5=6+(r=18=1+8=9
+6(fromPreviousCalc=
15=6&(e=5)+add(6+5=
11=1+1=2=(two=3)=(th
Ree=5)=(five=4)=(for
=3)=(three=4)=(four=
4)=(four=4)=(four=4)
���etc�
(BUTTden=?)
U didn,t hear "I.T."
From"ME"•••NOW send
"ME"da $29=(twenty-
Nine=11)=$2=(two=3)=
(Three=5)=(five=4)=
(Four=4)=(four=4)=
(Four=4)=(four=4)=
[REPEAT]••• ��

.


(Per: J.G.Wood(WORTH) inFAmercials)


" WherZ' "ME" Money CUZ "ME" NEEDS I.T. NOW ! "


" F'n-A "


.
Rick_bari3(at)NOTatBbMaleBUTt@Gmail•ComByteME
2008-05-16 23:02:12 UTC
Permalink
.
Post by Rick_bari3(at)***@Gmail•ComByteME
  Edited for stupidity
- Hide quoted text -
- Show quoted text -
Post by Rick_bari3(at)***@Gmail•ComByteME
Is it true? Does it work? Have you heard of it before? The formula
says that if you take the combination of any previous lottery draw
comprising a numerical string of all two-digit numbers in ascending
order and multiply them factorially excluding zeros (e.g. 54321
multiplied factorially = 5x4x3x2x1=120) it could yield a secretly
seeded sequence of two digit numbers which if large enough can be
arranged in ascending order with a key to the power ball or mega
number. If the resulting remainder is within 1 digit of an even number
[ :-)) } and divisible serially by 2 until the quotient equals a value
of 27 or less, this will yield the mega number in most state
lotteries. This formula only works with larger sequences of numbers
which is why winning draws rarely if ever correspond to a low sequence
of numbers like the one shown in the factorial example above. This is
no accident. It is designed that way by the statisticians who run the
lottery. This formula allows the lottery prize to be split up among
designated conspirators. My life may be in jeopardy. Good luck and
keep this to yourselves.
-Bozo-
(NUMBeroLOGee=3) cuz
12 is 1+2=3...der4,
De (NUMBers=7) 54321
Wood(LOG) Be,
5+4=9+3=12=1+2=3+2=5
+1=6BUT6=(six=3)&3=
(Three=5)BUT5=(five=
4BUT4=(four=4)BUT4=
(For=3)BUT3=(tree=4)
BUT4=(fore=4)ON-dee-
OtherHAND(fore-can-
BE-calculated/break-
Down.e.g.s(f=5)+(o=
15=1+5=6+(r=18=1+8=9
+6(fromPreviousCalc=
15=6&(e=5)+add(6+5=
11=1+1=2=(two=3)=(th
Ree=5)=(five=4)=(for
=3)=(three=4)=(four=
4)=(four=4)=(four=4)
•••etc•
(BUTTden=?)
U didn,t hear "I.T."
From "ME"•••
.- Hide quoted text -
- Show quoted text -
PFF (pretty effing funny)
-Bzpop-- Hide quoted text -
- Show quoted text -
(NUMBeroLOGee=3) cuz
12 is 1+2=3...der4,
De (NUMBers=7) 54321
Wood(LOG) Be,
5+4=9+3=12=1+2=3+2=5
+1=6BUT6=(six=3)&3=
(Three=5)BUT5=(five=
4BUT4=(four=4)BUT4=
(For=3)BUT3=(tree=4)
BUT4=(fore=4)ON-dee-
OtherHAND(fore-can-
BE-calculated/break-
Down.e.g.s(f=5)+(o=
15=1+5=6+(r=18=1+8=9
+6(fromPreviousCalc=
15=6&(e=5)+add(6+5=
11=1+1=2=(two=3)=(th
Ree=5)=(five=4)=(for
=3)=(three=4)=(four=
4)=(four=4)=(four=4)
���etc�
(BUTTden=?)
U didn,t hear "I.T."
From"ME"•••NOW send
"ME"da $29=(twenty-
Nine=11)=$2=(two=3)=
(Three=5)=(five=4)=
(Four=4)=(four=4)=
(Four=4)=(four=4)=
[REPEAT]••• ��
.
(Per: J.G.Wood(WORTH) inFAmercials)
" WherZ' "ME" Money CUZ "ME" NEEDS I.T. NOW ! "
" F'n-A "
.
. <
Bozo
2008-05-16 08:35:44 UTC
Permalink
Post by Rick_bari3(at)***@Gmail•ComByteME
Is it true? Does it work? Have you heard of it before?  The formula
says that if you take the combination of any previous lottery draw
comprising a numerical string of all two-digit numbers in ascending
order and multiply them factorially excluding zeros (e.g. 54321
multiplied factorially = 5x4x3x2x1=120) it could yield a secretly
seeded sequence of two digit numbers which if large enough can be
arranged in ascending order with a key to the power ball or mega
number. If the resulting remainder is within 1 digit of an even number
[ :-)) } and divisible serially by 2 until the quotient equals a value
of 27 or less, this will yield the mega number in most state
lotteries. This formula only works with larger sequences of numbers
which is why winning draws rarely if ever correspond to a low sequence
of numbers like the one shown in the factorial example above. This is
no accident. It is designed that way by the statisticians who run the
lottery. This formula allows the lottery prize to be split up among
designated conspirators. My life may be in jeopardy. Good luck and
keep this to yourselves.
-Bozo-
(NUMBeroLOGee=3) cuz
12 is 1+2=3...der4,
De (NUMBers=7) 54321
Wood(LOG) Be,
5+4=9+3=12=1+2=3+2=5
+1=6BUT6=(six=3)&3=
(Three=5)BUT5=(five=
4BUT4=(four=4)BUT4=
(For=3)BUT3=(tree=4)
BUT4=(fore=4)ON-dee-
OtherHAND(fore-can-
BE-calculated/break-
Down.e.g.s(f=5)+(o=
15=1+5=6+(r=18=1+8=9
+6(fromPreviousCalc=
15=6&(e=5)+add(6+5=
11=1+1=2=(two=3)=(th
Ree=5)=(five=4)=(for
=3)=(three=4)=(four=
4)=(four=4)=(four=4)
•••etc•
(BUTTden=?)
U didn,t hear "I.T."
From "ME"•••
.- Hide quoted text -
- Show quoted text -
PFF (pretty effing funny)

-Bzpop-
Rick_bari3(at)NOTatBbMaleBUTt@Gmail•ComByteME
2008-05-16 14:31:43 UTC
Permalink
Post by Bozo
Post by Rick_bari3(at)***@Gmail•ComByteME
Is it true? Does it work? Have you heard of it before?  The formula
says that if you take the combination of any previous lottery draw
comprising a numerical string of all two-digit numbers in ascending
order and multiply them factorially excluding zeros (e.g. 54321
multiplied factorially = 5x4x3x2x1=120) it could yield a secretly
seeded sequence of two digit numbers which if large enough can be
arranged in ascending order with a key to the power ball or mega
number. If the resulting remainder is within 1 digit of an even number
[ :-)) } and divisible serially by 2 until the quotient equals a value
of 27 or less, this will yield the mega number in most state
lotteries. This formula only works with larger sequences of numbers
which is why winning draws rarely if ever correspond to a low sequence
of numbers like the one shown in the factorial example above. This is
no accident. It is designed that way by the statisticians who run the
lottery. This formula allows the lottery prize to be split up among
designated conspirators. My life may be in jeopardy. Good luck and
keep this to yourselves.
-Bozo-
(NUMBeroLOGee=3) cuz
12 is 1+2=3...der4,
De (NUMBers=7) 54321
Wood(LOG) Be,
5+4=9+3=12=1+2=3+2=5
+1=6BUT6=(six=3)&3=
(Three=5)BUT5=(five=
4BUT4=(four=4)BUT4=
(For=3)BUT3=(tree=4)
BUT4=(fore=4)ON-dee-
OtherHAND(fore-can-
BE-calculated/break-
Down.e.g.s(f=5)+(o=
15=1+5=6+(r=18=1+8=9
+6(fromPreviousCalc=
15=6&(e=5)+add(6+5=
11=1+1=2=(two=3)=(th
Ree=5)=(five=4)=(for
=3)=(three=4)=(four=
4)=(four=4)=(four=4)
•••etc•
(BUTTden=?)
U didn,t hear "I.T."
From "ME"•••
.- Hide quoted text -
- Show quoted text -
PFF (pretty effing funny)
-Bzpop-- Hide quoted text -
- Show quoted text -
(NUMBeroLOGee=3) cuz
12 is 1+2=3...der4,
De (NUMBers=7) 54321
Wood(LOG) Be,
5+4=9+3=12=1+2=3+2=5
+1=6BUT6=(six=3)&3=
(Three=5)BUT5=(five=
4BUT4=(four=4)BUT4=
(For=3)BUT3=(tree=4)
BUT4=(fore=4)ON-dee-
OtherHAND(fore-can-
BE-calculated/break-
Down.e.g.s(f=5)+(o=
15=1+5=6+(r=18=1+8=9
+6(fromPreviousCalc=
15=6&(e=5)+add(6+5=
11=1+1=2=(two=3)=(th
Ree=5)=(five=4)=(for
=3)=(three=4)=(four=
4)=(four=4)=(four=4)
���etc�
(BUTTden=?)
U didn,t hear "I.T."
From"ME"•••NOW send
"ME"da $29=(twenty-
Nine=11)=$2=(two=3)=
(Three=5)=(five=4)=
(Four=4)=(four=4)=
(Four=4)=(four=4)=
[REPEAT]••• ��

.


(Per: J.G.Wood(WORTH) inFAmercials)

" WherZ' "ME" Money CUZ "ME" NEEDS I.T. NOW ! "


" F'n-A "





.
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